Can anyone tell me what the numbers should stay at.do you want the cc to be 0.a little confused but will to learn
Can anyone tell me what the numbers should stay at.do you want the cc to be 0.a little confused but will to learn
Good readings for an AG pool:
FC 3-6
TC 3-6
CC 0
CYA 30-40
Ph 7.4-7.6 (but anywhere 7.2-7.8 is OK)
Alk 80-125
Calcium Hardness - not needed in vinyl pool
Hope this helps. Keep reading the forum and if you haven't already done so, go and read at the sister site www.poolsolutions.com You will learn a lot.
If you have an 18x33 oval 4 feet deep, your volume would be APROX 15,500 gallons (actually 15,692). But that's assuming your WATER is 4 feet deep. If it's actually 3' 6" deep, you have 13,750gal, approx. (use 14,000 gallons in your estimates) If it's 3' 9", you have 14700 gal, aprox.(use 14,500 or 15,000 gallons in your estimates).
Carl
How did you calulate the volume of water
thanks
Magic!
No, not really. Just some simple geometry. An 18'x33' pool is an oval.
This oval is made up of a rectangle that's 15'x18' and a circle that's 18' in diameter. The circle is cut in half and each half is stuck on the ends of the rectangle.
The area of a rectangle is Length x Width. The area of a circle is PI * R squared, where PI is 3.146 and R is the radius--9' (half the diameter).
So...15'x18'= 270 square feet.
PI* R^2
=3.1416*9*9
=3.1416*81
=255 sq ft (approx).
So the area of the oval is
270 + 255 = 525 sq ft.
The volume of the pool is
area * depth, or
525 * 4
=2100 cubic feet.
Here's the part you might not know: One cubic foot contains 7.48 gallons. So
7.48*2100
=15,708 gallons.
Use 3.5 or 3.75 to get the other volumes.
Carl
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