Carl,
If you use a sheet to separate the fresh water that has no CYA from the pool water you are diluting that has CYA, then you are right, it doesn't matter how much drain or refill you do in what combination because there is no mixing of these two waters until you are finished adding and removing the total amount.
However, if you do not use a sheet and allow the water you are adding to mix with the existing pool water (say, by draining from one end of the pool while simultaneously filling from the other end, all while the pump is running), then it will take more water to achieve the same dilution compared to the sheet method.
A simple example will demonstrate this. Let's use your numbers of a pool with 20,000 gallons and 100 ppm CYA and you have fresh water you can add that has no CYA in it. If you want to get 50 ppm CYA then using a sheet to separate the fresh water from the pool water, you only need 10,000 gallons for dilution. However, let's do the dilution allowing the water to mix and let's do it in two steps with 5,000 gallons each. So, do the following:
1) Start with 20,000 gallons at 100 ppm CYA
2) Drain 5,000 gallons so you have 15,000 gallons at 100 ppm CYA (remember "ppm" is a concentration so draining doesn't change this, though evaporation would)
3) Add 5,000 gallons of fresh water. This gives you (5,000*0 + 15,000*100)/20,000 = 75 ppm CYA in 20,000 gallons
4) Drain 5,000 gallons again so you have 15,000 gallons at 75 ppm CYA
5) Add 5,000 gallons of fresh water. This gives you (5,000*0 + 15,000*75)/20,000 = 56.25 ppm CYA
Notice that replacing 10,000 gallons of water in two drain/refill steps only gets you to 56.25 ppm CYA and not 50 ppm CYA as you would get in one 10,000 gallon drain/refill step. If you replace less water each time and have more replacements, then you will get even less dilution. Notice that the formula is really
( (20,000 - 10,000/N) / 20,000 )^N * 100
where "N" is the number of water replacements. So doing only 100 gallons at a time would be 10,000/100 = 100 water replacements
( (20,000 - 10,000/100) / 20,000)^100 * 100 = 60.577 ppm CYA
"e" is defined as the limit of (1 + 1/N)^N as N goes to infinity so you can see the similarity of this with the above formula since the above formula in the limit as N goes to infinity (i.e. continuous dilution) is just e^(-0.5) * 100 = 60.653 ppm CYA which you can see is quite close to what happens with 100 water replacements.
The natural logarithm in the formula in my earlier post comes about because we are solving for how much fill water is needed as opposed to starting with a certain amount of fill water and solving for the dilution result.
Richard
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