Re: Breakpoint Chlorination

Originally Posted by
chem geek
Eight gallons of 12.5% liquid chlorine is (8 gal) * (3785.4118 ml/gal) * (0.125 g NaOCl / g solution) * (1.16 g/ml 12% NaOCl solution) * (52.46 g/mole HOCl) * (1000 mg/g) / (74.4424 g/mole NaOCl) / (20000 gal) * (3.7854118 l/gal) = 40.9 ppm
I believe you got to 50 ppm by neglecting to account for the difference in molecular weights between sodium hypochlorite (NaOCl) and hypochloric acid (HOCl) assuming that the 12.5% refers to the percent weight of sodium hypochlorite and the density of the 12% NaOCl solution.
Actually, I used BleachCalc to figure it out...I'm lazy!
Maybe this old-time pool guy was using a diluted ammonia that really was not anhydrous. To achieve breakpoint, you should have 3*3 = 9, so round and say 10 times as much ppm chlorine as ammonia.
This acually came from the book "The Ultimate Pool Maintenance Manual, second edition by Terry Tamminen. 7th printing McGraw-Hill 2001. The author suggested that monochoramines would form and help kill any algae that might be present. However, he did give it as a recipe for breakpoint chlorination.
Richard
Just goes to show how much misinformation there is about pools. This book is considered to be one of the "best" referrences for pool maintenance professionals generally available! I have found that much of the info is quite useful but much of it is just a rehash of 'old wives tales'. The problem lies with sorting out the truth from the tales!
Retired pool store and commercial pool maintenance guy.
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