How much CYA does one puck generate in a 10,000 gal pool?
How much CL does one puck generate in a 10,000 gal pool?
How much calcium does one puck generate in a 10,000 gal pool?
Looking forward to your replies.
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How much CYA does one puck generate in a 10,000 gal pool?
How much CL does one puck generate in a 10,000 gal pool?
How much calcium does one puck generate in a 10,000 gal pool?
Looking forward to your replies.
My answers below in bold assuming you are referring to one 3" diameter Tri-Chlor puck (first answer) or one 3/4" diameter Calcium Hypochlorite tablet (second answer).
Quote:
Originally Posted by smallpooldad
Chem Geek,
Once again thank you. Is it possible for you to supply the equations, when you have time?
I am having to prove a point to my next door neighbours pool persons and them.
If that is not possible I can understand.
Aloha
I'll try to keep this as brief as possible and hope you or your neighbor know enough about chemistry to believe the math.Quote:
Originally Posted by smallpooldad
Tri-Chlor + 3H2O --> CYA + 3HOCl
See the chemical structure for Tri-Chlor and CYA and notice that Tri-Chlor has 3 chlorine atoms that get replaced with hydrogen when dissolved in water. These chlorine atoms are Cl+, not chloride (Cl-) so they combine with OH- from water to form HOCl while the H+ from water becomes part of CYA (which is a weak acid).
(8 oz./tablet) * (28.349523 g/oz) / (232.4103 g/mole Tri-Chlor) = 0.9758 moles Tri-Chlor/tablet
(0.9758 moles/tablet) * (129.075 g/mole CYA) * (1000 mg/g) / ( (10,000 gallons) * (3.7854 liters/gallon) ) = 3.33 mg/l CYA = 3.33 ppm CYA
(0.9758 moles/tablet) * (3 chlorine/molecule) * (52.4603 g/mole HOCl) * (1000 mg/g) / ( (10,000 gallons) * (3.7854 liters/gallon) ) = 4.06 mg/l HOCl = 4.06 ppm chlorine
There is no calcium in Tri-Chlor so 0 ppm calcium.
Ca(OCl)2 + 2H2O --> Ca(2+) + 2HOCl + 2OH-
(7 g/tablet) / (142.98366 g/mole Ca(OCl)2) = 0.04896 moles Ca(OCl)2/tablet
There is no CYA in Ca(OCl)2 so 0 ppm CYA.
(0.04896 moles/tablet) * (2 chlorine/molecule) * (73%/100 purity) * (52.4603 g/mole HOCl) * (1000 mg/g) / ( (10,000 gallons) * (3.7854 liters/gallon) ) = 0.10 mg/l HOCl = 0.10 ppm chlorine
(0.04896 moles/tablet) * (73%/100 purity) * (100.0892 g/mole CaCO3) * (1000 mg/g) / ( (10,000 gallons) * (3.7854 liters/gallon) ) = 0.09 mg/l CaCO3 equivalent = 0.09 ppm "calcium hardness"
Richard
Chem Geek,
Once again thank you.
Hopefully they and I can figure this out.
Aloha