Pool test Here is my Numbers,What next?

[sisie5]

Just check my numbers this morning here are the results.I added cya three days ago,should I add more cya.what should I do next?

TC-1.5
CC-0.5
TC-2
PH-7.8
ALK-190
CYA-20

[ivyleager]

No, wait at least one week for CYA that is trapped in filter media to totally dissolve prior to adding more. Don't want to overshoot and have too much CYA. Good luck.

CaryB

[duraleigh]

Just check my numbers this morning here are the results.I added cya three days ago,should I add more cya.what should I do next?

TC-1.5
CC-0.5
TC-2
PH-7.8
ALK-190
CYA-20

Hi, Sisie5,

AS Cary said, wait a little longer on CYA. I'd put in enough Cl to bring the TC up to 12-15. That'll shock the pool and get that .5 CC out of there. Then let your TC come down on it's own to about 3-5 and keep it there. Yuu've made great progress.

I'd add enough muriatic acid to bring pH down to about 7.2 - 7.6. It's okay now but you don't want it any higher. How does your water look? :)

[sisie5]

Cary,my water looks very clear.when I added the cya I put it in a nylon hose and hung it by the skimmer,it took two days to deslove.how much cl do I add?

Thanks

[sisie5]

Oops my mistake I meant FC -1.5

[aylad]

Can't tell you how much chlorine to add without knowing how many gallons your pool holds..... :)

Janet

[sisie5]

My pool is an 18x33 oval 4 ft deep I don"t quick understand all this chemistry stuff yet.this will be my first year with the pool.

[sisie5]

Can anyone tell me what the numbers should stay at.do you want the cc to be 0.a little confused but will to learn

[Watermom]

Good readings for an AG pool:
FC 3-6
TC 3-6
CC 0
CYA 30-40
Ph 7.4-7.6 (but anywhere 7.2-7.8 is OK)
Alk 80-125
Calcium Hardness - not needed in vinyl pool

Hope this helps. Keep reading the forum and if you haven't already done so, go and read at the sister site www.poolsolutions.com You will learn a lot.

[CarlD]

If you have an 18x33 oval 4 feet deep, your volume would be APROX 15,500 gallons (actually 15,692). But that's assuming your WATER is 4 feet deep. If it's actually 3' 6" deep, you have 13,750gal, approx. (use 14,000 gallons in your estimates) If it's 3' 9", you have 14700 gal, aprox.(use 14,500 or 15,000 gallons in your estimates).

[sisie5]

How did you calulate the volume of water

thanks

[CarlD]

Magic!

No, not really. Just some simple geometry. An 18'x33' pool is an oval.

This oval is made up of a rectangle that's 15'x18' and a circle that's 18' in diameter. The circle is cut in half and each half is stuck on the ends of the rectangle.


The area of a rectangle is Length x Width. The area of a circle is PI * R squared, where PI is 3.146 and R is the radius--9' (half the diameter).

So...15'x18'= 270 square feet.
PI* R^2
=3.1416*9*9
=3.1416*81
=255 sq ft (approx).

So the area of the oval is
270 + 255 = 525 sq ft.

The volume of the pool is
area * depth, or
525 * 4
=2100 cubic feet.

Here's the part you might not know: One cubic foot contains 7.48 gallons. So
7.48*2100
=15,708 gallons.

Use 3.5 or 3.75 to get the other volumes.