View Full Version : 8.25% bleach
mastamoon
06-12-2014, 12:43 PM
8.25% bleach seems to be the new standard 'concentrated' strength. I tend to use pool calculator to work out my levels but it doesn't give 8.25 as an option down in the "Effect of adding chemicals" section. Could anybody tell me what adding 128 ounces of 8.25% bleach to a 10,000 gallon pool would give as PPM?
Thanks!
Pappy
06-12-2014, 12:59 PM
According to this
http://pool9.net/bleach-calc/
1 gallon of 8.25% bleach in 10,000 gallons adds 8.2 ppm chlorine.
The "More Calcs" tab in the upper left corner lets you access more calculators and settings (imperial vs. metric).
mastamoon
06-12-2014, 01:06 PM
Thanks! Guess that app doesn't like running in windows 8 much, even in compatibility mode. :(
Watermom
06-12-2014, 01:09 PM
No, that is one of the problems we have found with that calc. It doesn't like Win8.
mastamoon
06-12-2014, 01:53 PM
Ok, I had to setup a Windows XP virtual machine to check out the app.
The calculations between this app and www.poolcalculator.com dont really jive. I wonder which one is more accurate. The bleachcalc seems to be purely math... 1gal pool, 1 gal 5.25% bleach = 52500 ppm.. making it 10 gal pool just moves the decimal point. The poolcalculator says 54007 for the same values. I know its not enough to care about especially when you move the size of the pool up to 10000 gallons but I wonder where the poolcalculator is coming up with the difference.
let_her_flicker
06-14-2014, 05:46 PM
Here is the formula I use for manually calculating chlorine. 1,000,000/10,000 x .95 x 0.0825 = 7.8
One million divided by the total gallons of water in pool, then multiplied by .95 (121 oz of chlorine is converted to a decimal) x 0.0825 (% of chlorine in jug).
121 oz is the amount of bleach in the jugs of bleach I use.
Hope this helps you.
kelemvor
06-14-2014, 07:26 PM
The pool calculator website is client side scripting so you can see the calculation by viewing the source. Here's what it's doing:
parseFloat(document.F.FCto.value)-
parseFloat(document.F.FCfrom.value)) *
GetGallons() / 482.202 * 6 / parseFloat(document.F.FCpcnt.value);
document.F.FC1oz.value=PutVolume(temp);
Which is basically Target increase*water volume /482.202*6/LC strength
Perhaps the difference is in order of operations or that 482.202 constant. I'm not intimate enough with the formula to know what that is for. I wonder why they didn't use 2,893.212 for the constant.